How do you evaluate ${(x - y)}^{2} - 2 w z$ $(x-y)^2-2wz$ if w=6, x=0.4, y=1/2, z=-3?

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How do you evaluate ${(x - y)}^{2} - 2 w z$ $(x-y)^2-2wz$ if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-04-29T02:18:33

See the solution process below:

Explanation:

We need to do the following substitutions into the expression:

$6$ $color(red)(6)$ for $w$ $color(red)(w)$

$0.4$ $color(blue)(0.4)$ for $x$ $color(blue)(x)$

$\frac{1}{2}$ $color(green)(1/2)$ for $y$ $color(green)(y)$

$- 3$ $color(purple)(-3)$ for $z$ $color(purple)(z)$

${(x - y)}^{2} - 2 w z$ $(color(blue)(x) - color(green)(y))^2 - 2color(red)(w)color(purple)(z)$ becomes:

${(0.4 - \frac{1}{2})}^{2} - (2 \cdot 6 \cdot - 3) \Rightarrow$ $(color(blue)(0.4) - color(green)(1/2))^2 - (2 * color(red)(6) * color(purple)(-3)) =>$

${(0.4 - 0.5)}^{2} - (12 \cdot - 3) \Rightarrow$ $(color(blue)(0.4) - color(green)(0.5))^2 - (12 * color(purple)(-3)) =>$

${(- 0.1)}^{2} - (- 36) \Rightarrow$ $(-0.1)^2 - (-36) =>$

$0.01 + 36 \Rightarrow$ $0.01 + 36 =>$

$36.01$ $36.01$

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How do you evaluate ${(x - y)}^{2} - 2 w z$ $(x-y)^2-2wz$ if w=6, x=0.4, y=1/2, z=-3?

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Explanation:

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