How do you evaluate $(x+y)^3$ for x=22 and y=5?

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Answer 1 · 2017-01-10T22:35:10

See explanation below

You substitute $color(red)(22)$ for $x$ and $color(blue)(5)$ for $y$ and the calculate the value:

$(color(red)(x) + color(blue)(y))^3$ with substitution becomes:

$(color(red)(22) + color(blue)(5))^3 = 27^3 = 27 xx 27 xx 27 = 729 xx 27 = 19,683$

How do you evaluate (x+y)^3(x+y)^3 for x=22 and y=5?