How do you evaluate x + y for x= 4/5 and y=7/10?

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Answer 1 · 2015-06-12T23:05:03

$x + y = \frac{4}{5} + \frac{7}{10} = \frac{8}{10} + \frac{7}{10} = \frac{15}{10} = \frac{3}{2}$ $x+y = 4/5 + 7/10 = 8/10+7/10 = 15/10 = 3/2$

To add fractions, you first need to give them common denominators, then just add the numerators...

$x + y = \frac{4}{5} + \frac{7}{10}$ $x+y = 4/5 + 7/10$

$= \frac{2}{2} \cdot \frac{4}{5} + \frac{7}{10}$ $=2/2*4/5+7/10$

$= \frac{2 \cdot 4}{2 \cdot 5} + \frac{7}{10}$ $= (2*4)/(2*5) + 7/10$

$= \frac{8}{10} + \frac{7}{10}$ $= 8/10 + 7/10$

$= \frac{15}{10}$ $= 15/10$

$= \frac{3 \cdot 5}{2 \cdot 5}$ $= (3*5)/(2*5)$

$= \frac{3}{2} \cdot \frac{5}{5}$ $= 3/2*5/5$

$= \frac{3}{2}$ $= 3/2$