How do you evaluate xy - z, when x = -2, y = 3 and z = 1?

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How do you evaluate xy - z, when x = -2, y = 3 and z = 1?

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Answer 1 · 2018-03-10T14:23:24

$- 7$ $-7$

Explanation:

$substitute the given values into the expression$ $"substitute the given values into the expression"$

$\Rightarrow x y - z$ $rArrxy-z$

$= (- 2 \times 3) - 1$ $=(color(red)(-2)xxcolor(blue)(3))-color(magenta)(1)$

$= - 6 - 1 = - 7$ $=-6-1=-7$

Answer 2 · 2018-03-10T14:24:44

$x y - z = - 7$ $xy-z=-7$

Explanation:

When given an algebraic equation, we simply plug in the values.

$\to$ $->$ Note $x y$ $xy$ means $x \times y$ $x xx y$

$\to x y - z \to - 2 \times 3 - 1$ $-> xy-z -> -2xx3-1$

$- 2 \times 3 = - 6$ $-2xx3=-6$

$- 6 - 1 = - 7$ $-6-1=-7$

$therefore$ $xy-z=-7$

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How do you evaluate xy - z, when x = -2, y = 3 and z = 1?

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