How do you evaluate $z - w + y$ $z-w+y$ if w=6, x=4, y=-2, z=6?

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Answer 1 · 2017-06-06T01:49:38

See a solution process below:

The $x$ $x$ valuable is not in the expression and is therefore extraneous and does not need to be considered in the solution.

We can then substitute:

$6$ $color(red)(6)$ for $w$ $color(red)(w)$

$- 2$ $color(blue)(-2)$ for $y$ $color(blue)(y)$

$6$ $color(green)(6)$ for $z$ $color(green)(z)$

in the expression and calculate the result:

$z - w + y$ $color(green)(z) - color(red)(w) + color(blue)(y)$ becomes:

$6 - 6 + - 2 \Rightarrow$ $color(green)(6) - color(red)(6) + color(blue)(-2) =>$

$0 + - 2 \Rightarrow$ $0 + color(blue)(-2) =>$

$- 2$ $-2$

How do you evaluate z−w+yz-w+y if w=6, x=4, y=-2, z=6?