How do you expand ln((3x^2y^3) /22)ln(3x2y322)?

1 Answer
Nov 30, 2015

=ln(3/22)+2ln(x)+3ln(y)=ln(322)+2ln(x)+3ln(y)

Explanation:

{(ln((ab)/c)=ln(a)+ln(b)-ln(c)),(ln(a^b)=bln(a)):}

ln((3x^2y^3)/22)=ln(3)+ln(x^2)+ln(y^3)-ln(22)

ln(3)+2ln(x)+3ln(y)-ln(22)

=ln(3/22)+2ln(x)+3ln(y)