How do you expand $ln (xe^x)$ ?

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Answer 1 · 2018-03-25T12:51:47

$lnxe^x = x+lnx$

To expand $lnxe^x$ , we use the following property

$logab=log a+logb$

So

$lnxe^x=lnx+lne^x=x+lnx$

How do you expand ln (xe^x)ln (xe^x)?