How do you expand $log (\frac{a^{4}}{b^{3} \sqrt{c}})$ $log (a^4/(b^3sqrtc))$ ?

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Answer 1 · 2016-06-12T13:42:03

$= 4 log a - 3 log b - \frac{1}{2} log c$ $=4log a - 3logb - 1/2logc$

Break the term into separate log terms first:

$log (\frac{a^{4}}{b^{3} \sqrt{c}}) = {log a}^{4} - {log b}^{3} - log \sqrt{c}$ $log(a^4/(b^3 sqrtc)) = log a^4 - logb^3 - logsqrtc$

Now apply some some log and indices laws

= $4 log a - 3 log b - {log c}^{\frac{1}{2}}$ $4log a - 3logb - logc^(1/2)$

$= 4 log a - 3 log b - \frac{1}{2} log c$ $=4log a - 3logb - 1/2logc$

How do you expand log (a^4/(b^3sqrtc))log(a4b3√c)log (a^4/(b^3sqrtc))?