How do you expand #log (a^4/(b^3sqrtc))#?

1 Answer
EZ as pi
Jun 12, 2016

#=4log a - 3logb - 1/2logc#

Explanation:

Break the term into separate log terms first:

#log(a^4/(b^3 sqrtc)) = log a^4 - logb^3 - logsqrtc#

Now apply some some log and indices laws

=#4log a - 3logb - logc^(1/2)#

#=4log a - 3logb - 1/2logc#

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