How do you factor $12 n^{3} - 8 n$ $12n^3 - 8n$ ?

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Answer 1 · 2016-07-20T16:51:57

$4 n (3 n^{2} - 2)$ $4n(3n^2 - 2)$

Always look for a common factor first. In this case $4 n$ $4n$

Divide each term by $4 n$ $4n$ and write the answers (quotients)in the bracket. I often think about them as "the left-overs".

$4 n (3 n^{2} - 2)$ $4n(3n^2 - 2)$

How do you factor 12n3−8n12n^3 - 8n?