How do you factor $15 x^{5} - 10 x^{4} + 5 x^{2}$ $15x^5-10x^4+5x^2$ ?

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Answer 1 · 2017-03-02T07:05:38

$15 x^{5} - 10 x^{4} + 5 x^{2} = 5 x^{2} (3 x^{3} - 2 x^{2} + 1)$ $15x^5-10x^4+5x^2=5x^2(3x^3-2x^2+1)$

In the polynomial $15 x^{5} - 10 x^{4} + 5 x^{2}$ $15x^5-10x^4+5x^2$ , we have three monomials

$15 x^{5}$ $15x^5$ , $- 10 x^{4}$ $-10x^4$ and $5 x^{2}$ $5x^2$

As their GCF is $5 x^{2}$ $5x^2$ , we can take this common

and therefore, dividing each monomial by $5 x^{2}$ $5x^2$ , we get

$3 x^{3}$ $3x^3$ , $- 2 x^{2}$ $-2x^2$ and $1$ $1$ .

Hence $15 x^{5} - 10 x^{4} + 5 x^{2} = 5 x^{2} (3 x^{3} - 2 x^{2} + 1)$ $15x^5-10x^4+5x^2=5x^2(3x^3-2x^2+1)$

How do you factor 15x^5-10x^4+5x^2 15x5−10x4+5x215x^5-10x^4+5x^2 ?