How do you factor $28a^3b^4+20a^2b^2-16ab^3$ ?

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Answer 1 · 2017-01-03T20:03:18

Let's first take out the numbers

$=4xx(7a^3b^4+5a^2b^2-4ab^3)$

From every term we can take out $ab^2$
$=4ab^2(7a^2b^2+5a-4b)$

How do you factor 28a^3b^4+20a^2b^2-16ab^328a^3b^4+20a^2b^2-16ab^3?