How do you factor $2a^3-128$ ?

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Answer 1 · 2016-07-04T03:08:16

$(a - 4)(a^2 + 4a + 16)$

Apply the algebraic formula:
$a^3 - b^3 = (a - b) (a^2 + ab + b^2)$
$y = 2(a^3 - 64) = 2(a^3 - 4^3) = 2(a - 4)(a^2 + 4a + 16)$

How do you factor 2a^3-1282a^3-128?