How do you factor $2 x^{2} - 18$ $2x^2- 18$ ?

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Answer 1 · 2015-09-28T21:43:23

The answer is $2 (x + 3) (x - 3)$ $2(x+3)(x-3)$ .

$2 x^{2} - 18$ $2x^2-18$

Factor out the GCF $2$ $2$ .

$2 (x^{2} - 9)$ $2(x^2-9)$

$x^{2} - 9$ $x^2-9$ fits the form $a^{2} - b^{2}$ $a^2-b^2$ , where $a = x and b = 3$ $a=x and b=3$ .

Rewrite the expression.

$2 (x^{2} - 3^{2})$ $2(x^2-3^2)$

$a^{2} - b^{2} = (a + b) (a - b)$ $a^2-b^2=(a+b)(a-b)$

$2 (x + 3) (x - 3)$ $2(x+3)(x-3)$

How do you factor 2x^2- 182x2−182x^2- 18?