How do you factor $32 - 18 x^{2}$ $32 - 18x^2$ ?

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Answer 1 · 2015-10-01T06:19:26

First separate out the common scalar factor $2$ $2$ , then use the difference of squares identity to find:

$32 - 18 x^{2} = 2 (4 - 3 x) (4 + 3 x)$ $32 - 18x^2 = 2(4-3x)(4+3x)$

The difference of squares identity is: $a^{2} - b^{2} = (a - b) (a + b)$ $a^2 - b^2 = (a-b)(a+b)$

Using $a = 4$ $a = 4$ and $b = 3 x$ $b = 3x$ , we find:

$32 - 18 x^{2} = 2 (16 - 9 x^{2}) = 2 (4^{2} - {(3 x)}^{2}) = 2 (4 - 3 x) (4 + 3 x)$ $32 - 18x^2 = 2(16-9x^2) = 2(4^2 - (3x)^2) = 2(4-3x)(4+3x)$

How do you factor 32−18x232 - 18x^2?