Question

How do you factor `3ax-6bx+8b-4a`?

Answer 1

`(a-2b)(3x-4)`

Explanation:

`"factorise in 2 groups"`

`rArrcolor(red)(3x)(a-2b)color(red)(-4)(a-2b)`

`"take out the common factor "(a-2b)`

`=(a-2b)(color(red)(3x-4))`

`rArr3ax-6bx+8b-4a=(a-2b)(3x-4)`