How do you factor $3 x^{2} - 8 x = - 4$ $3x^2 - 8x = -4$ ?

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How do you factor $3 x^{2} - 8 x = - 4$ $3x^2 - 8x = -4$ ?

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Answer 1 · 2018-07-15T11:30:02

$(x - 2) (3 x - 2) = 0$ $(x-2)(3x-2)=0$

Explanation:

$add 4 to both sides$ $"add 4 to both sides"$

$3 x^{2} - 8 x + 4 = 0 \leftarrow in standard form$ $3x^2-8x+4=0larrcolor(blue)"in standard form"$

$using the a-c method to factor the quadratic$ $"using the a-c method to factor the quadratic"$

$the factors of the product 3 \times 4 = 12$ $"the factors of the product "3xx4=12$

$which sum to - 8 are - 6 and - 2$ $"which sum to "-8" are "-6" and "-2$

$split the middle term using these factors$ $"split the middle term using these factors"$

$3 x^{2} - 6 x - 2 x + 4 = 0 \leftarrow factor by grouping$ $3x^2-6x-2x+4=0larrcolor(blue)"factor by grouping"$

$3 x (x - 2) - 2 (x - 2) = 0$ $color(red)(3x)(x-2)color(red)(-2)(x-2)=0$

$take out the common factor (x - 2)$ $"take out the "color(blue)"common factor "(x-2)$

$(x - 2) (3 x - 2) = 0$ $(x-2)(color(red)(3x-2))=0$

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How do you factor $3 x^{2} - 8 x = - 4$ $3x^2 - 8x = -4$ ?

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How do you factor $3 x^{2} - 8 x = - 4$ $3x^2 - 8x = -4$ ?