How do you factor $6abc^(2) - 14a^(2)bc + 4ab^(2)c$ ?

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Answer 1 · 2016-06-30T16:33:50

$2abc(3c-7a+2b)$

Always look for a common factor first.
There is a common factor of $2abc$ which can be divided out of each term.

$6abc^(2) - 14a^(2)bc + 4ab^(2)c$

= $2abc(3c-7a+2b)$

How do you factor 6abc^(2) - 14a^(2)bc + 4ab^(2)c6abc^(2) - 14a^(2)bc + 4ab^(2)c?