Question

How do you factor and simplify `sin^3x+27`?

Answer 1

`sin^3x+27=(sinx+3)(sin^2-3sinx+9)`

Explanation:

`sin^3x+27`

= `((sinx)^3+3^3)`

Now using identity `a^3+b^3=(a+b)(a^2-ab+b^2)`

this is `(sinx+3)(sin^2-3sinx+9)`