How do you factor and solve $25x^2 -9 =0$ ?

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Answer 1 · 2016-07-12T00:12:11

$x in {-3/5, 3/5}$

Using the difference of squares formula $a^2-b^2 = (a+b)(a-b)$ , we have

$25x^2 - 9 = (5x)^2-3^2=(5x+3)(5x-3) = 0$

$=>5x+3 = 0 or 5x-3 = 0$

$=> 5x = -3 or 5x = 3$

$=> x = -3/5 or x = 3/5$

How do you factor and solve 25x^2 -9 =025x^2 -9 =0?