How do you factor and solve $2x^2=5x+12$ ?

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Answer 1 · 2016-09-06T16:29:21

$x = 4 or x = -3/2$

$2x^2 - 5x -12 =0$

or, $2x^2 - 8x + 3x - 12 = 0$

or, $2x(x - 4) + 3(x - 4) = 0$

or, $(x - 4)(2x + 3) = 0$

$rarr x = 4 and x = - 3/2$

How do you factor and solve 2x^2=5x+122x^2=5x+12?