How do you factor and solve $2 x^{2} - 6 x + 4 = 0$ $2x^2-6x+4=0$ ?

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Answer 1 · 2016-08-05T21:47:31

$x = 1 or x = 2$ $x=1 or x=2$

Notice that all the coefficients are even.
We can therefore divide by 2 to simplify matters.

$2 x^{2} - 6 x + 4 = 0 \div 2$ $2x^2 - 6x + 4 = 0" "div 2$

$x^{2} - 3 x + 2 = 0$ $x^2 -3x +2 = 0" "$ Find the factors of 2 which add up to 3.

$(x - 2) (x - 1) = 0$ $(x-2)(x-1) = 0$

Each factor could be equal to 0.
$x - 2 = 0 \Rightarrow x = 2$ $x- 2 = 0 rArr x = 2$

$x - 1 = 0 \Rightarrow x = 1$ $x-1 = 0 rArr x = 1$

How do you factor and solve 2x2−6x+4=02x^2-6x+4=0?