How do you factor and solve $3 x^{2} - 12 x = 0$ $3x^2-12x=0$ ?

Question

12408 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-14T09:16:32

$3 x (x - 4) = 0 \to x = 0 or x = 4$ $3x(x-4)=0 -> x=0 or x=4$

$3 x^{2} - 12 x = 0$ $3x^2-12x=0$

Factorise:
$3 x (x - 4) = 0$ $3x(x-4)=0$

Hence,

either $3 x = 0 \to x = 0$ $3x=0 -> x=0$
or $(x - 4) = 0 \to x = 4$ $(x-4) = 0 -> x=4$

How do you factor and solve 3x^2-12x=0 3x2−12x=03x^2-12x=0 ?