How do you factor and solve $6 x^{2} - 53 x - 9 = 0$ $6x^2 - 53x -9 =0$ ?

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How do you factor and solve $6 x^{2} - 53 x - 9 = 0$ $6x^2 - 53x -9 =0$ ?

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Answer 1 · 2016-06-04T21:32:00

(6x + 1)(x - 9) = 0

Explanation:

since you have a number greater then 1 at the $x^{2}$ $x^2$ you would multiply that by -9 (the last digit in the equation) and arrive at -54. then you need two numbers that add to -53 and multiply to -54. the only two numbers that satisfy this are 1 and -54.

group the equation so that you can factor it further

$6 x^{2} - 54 x + x - 9 = 0$ $6x^2-54x+x-9=0$

$6 x (x - 9) + 1 (x - 9) = 0$ $6x(x-9) +1(x-9)=0$

$(6 x + 1) (x - 9) = 0$ $(6x+1)(x-9)=0$

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How do you factor and solve $6 x^{2} - 53 x - 9 = 0$ $6x^2 - 53x -9 =0$ ?

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Explanation:

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Science

Math

Humanities

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How do you factor and solve 6x^2 - 53x -9 =06x2−53x−9=06x^2 - 53x -9 =0?

1 Answer

Explanation:

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How do you factor and solve $6 x^{2} - 53 x - 9 = 0$ $6x^2 - 53x -9 =0$ ?