How do you factor and solve $x^{2} - 10 x = - 16$ $x^2 - 10x = -16$ ?

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Answer 1 · 2016-08-05T22:12:14

$(x - 8) (x - 2) = 0$ $(x-8)(x-2)= 0$
$x = 8 or x = 2$ $x=8 or x=2$

Make quadratic equations equal to 0.

$x^{2} - 10 x + 16 = 0 find factors of 16 which add up to 10$ $x^2 -10x +16 =0" find factors of 16 which add up to 10"$

The signs are the same, they are both minus.

$(x - 8) (x - 2)$ $(x-8)(x-2)$

Either factor can be equal to 0.
$x - 8 = 0, \Rightarrow x = 8$ $x-8 = 0, rArr x = 8$
$x - 2 = 0, \Rightarrow x = 2$ $x-2 = 0, rArr x=2$

How do you factor and solve x2−10x=−16x^2 - 10x = -16?