How do you factor and solve $x^{2} - 14 x + 42 = 0$ $x^2 - 14x + 42 = 0$ ?

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How do you factor and solve $x^{2} - 14 x + 42 = 0$ $x^2 - 14x + 42 = 0$ ?

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Answer 1 · 2017-07-21T04:55:59

$x = 7 \pm i \sqrt{6}$ $x = 7 +- isqrt6$

Explanation:

$y = x^{2} - 14 x + 42 = 0$ $y = x^2 - 14x + 42 = 0$
Use the quadratic formula in graphic form (Socratic, Google Search)
$D = d^{2} = b^{2} - 4 a c = 144 - 168 = - 24$ $D = d^2 = b^2 - 4ac = 144 - 168 = - 24$
There are 2 imaginary roots.
$D = d^{2} = 24 i^{2}$ $D= d^2 = 24i^2$ --> $d = \pm 2 i \sqrt{6}$ $d = +- 2isqrt6$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{14}{2} \pm \frac{2 i \sqrt{6}}{2} = 7 \pm i \sqrt{6}$ $x = -b/(2a) +- d/(2a) = 14/2 +- (2isqrt6)/2 = 7 +- isqrt6$

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How do you factor and solve $x^{2} - 14 x + 42 = 0$ $x^2 - 14x + 42 = 0$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you factor and solve x2−14x+42=0x^2 - 14x + 42 = 0 ?

1 Answer

Explanation:

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How do you factor and solve $x^{2} - 14 x + 42 = 0$ $x^2 - 14x + 42 = 0$ ?