Question

How do you factor and solve `x^2 + 3x = 28`?

Answer 1

(x - 4)(x + 7)

Explanation:

`y = x^2 + 3x - 28 = 0`
To factor it, find 2 numbers knowing sum (b = 3) and product (c = -28).
They make the factor pair: (-4, 7).
`y = (x - 4)(x + 7)`
The 2 real roots are x = 4 and x = -7