Question

How do you factor and solve `x^2+4=5x`?

Answer 1

We have that

`x^2+4=5x=>x^2-x+4-4x=0=>x*(x-1)-4(x-1)=0=> (x-1)*(x-4)=0`

Hence the solutions are `x_1=1` and `x_2=4`