How do you factor and solve $x^{2} + 4 x - 3 = 0$ $x^2+4x-3=0$ ?

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Answer 1 · 2018-01-05T20:54:58

It doesn't factorise but it can still be solved, for example : By completing the square.

So let's complete the square.

$therefore$ $x^2+4x-3 = (x+2)^2-4-3=0$
$therefore (x+2)^2-7=0$

Now lets solve:

$(x+2)^2-7=0$
$(x+2)^2=7$
$x+2=+-sqrt(7)$
$x=-2+-sqrt(7)$

Therefore X has been solved

$x=-2+sqrt(7)$ or $x=-2-sqrt(7)$

How do you factor and solve x^2+4x-3=0x2+4x−3=0x^2+4x-3=0?