How do you factor and solve $x^2+4x+4=0$ ?

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Answer 1 · 2016-09-19T21:46:56

$x = - 2$

We have: $x^(2) + 4 x + 4 = 0$

Let's factorise this equation using the middle-term break:

$=> x^(2) + 2 x + 2 x + 4 = 0$

$=> x (x + 2) + 2 (x + 2) = 0$

$=> (x + 2) (x + 2) = 0$

$=> (x + 2)^(2) = 0$

$=> x + 2 = 0$

$=> x = - 2$

Therefore, the solution to the equation is $x = - 2$ .

How do you factor and solve x^2+4x+4=0 x^2+4x+4=0 ?