How do you factor and solve x^2-8x=-3x2−8x=−3?

1 Answer
F. Javier B.
Mar 7, 2018

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Explanation:

Put the equation in form

x^2-8x+3=0x2−8x+3=0

From here we have two options:

Option a) Use the solutions formula for 2nd degree equations

x=(-b+-sqrt(b^2-4ac))/(2a)x=−b±√b2−4ac2a for a equ in the canonic form

ax^2+bx+c=0ax2+bx+c=0

On this way: x=(8+-sqrt(64-12))/2=(8+-sqrt(4·13))/2=4+-sqrt13x=8±√64−122=8±√4⋅132=4±√13

Option b) complete the square

x^2-8x+3=(x-4)^2-16+3=(x-4)^2-13=(x-4+sqrt13)(x-4-sqrt13)x2−8x+3=(x−4)2−16+3=(x−4)2−13=(x−4+√13)(x−4−√13) from here the solutions are 4+-sqrt134±√13

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