How do you factor $e^{2 x} + 2 e^{- 2 x}$ $e^(2x) +2 e^(-2x)$ ?

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How do you factor $e^{2 x} + 2 e^{- 2 x}$ $e^(2x) +2 e^(-2x)$ ?

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Answer 1 · 2015-03-28T10:27:28

The answer is:

$e^{2 x} + 2 e^{- 2 x} = e^{- 2 x} (\frac{e^{2 x}}{e^{- 2 x}} + 2) = e^{- 2 x} (e^{4 x} + 2)$ $e^(2x) +2 e^(-2x)=e^(-2x)(e^(2x)/e^(-2x)+2)=e^(-2x)(e^(4x)+2)$ .

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How do you factor $e^{2 x} + 2 e^{- 2 x}$ $e^(2x) +2 e^(-2x)$ ?

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