How do you factor $n^2+5n+7$ ?

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Answer 1 · 2015-10-01T21:56:41

$n=((-5+sqrt(3)i)/2),((-5-sqrt(3)i)/2)$

$n^2+5n+7$ is a quadratic equation $ax^2+bx+c$ , where $a=1, b=5, c=7$ .

You can use the quadratic formula to factor this quadratic equation.

Quadratic Formula

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Substitute $n$ for $x$ .

$n=(-5+-sqrt(5^2-4*1*7))/(2*1)=$

Simplify.

$n=(-5+-sqrt(25-28))/2=$

Simplify.

$n=(-5+-sqrt(-3))/2=$

Simplify.

$n=(-5+-sqrt(3)i)/2=$

$n=((-5+sqrt(3)i)/2),((-5-sqrt(3)i)/2)$

How do you factor n^2+5n+7n^2+5n+7?