How do you factor the polynomials $18 r^{3} t^{2} + 12 r^{2} t^{2} - 6 r^{2} t$ $18r^3t^2+12r^2t^2-6r^2t$ ?

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Answer 1 · 2018-04-18T23:18:36

It's

$18 r^{3} t^{2} + 12 r^{2} t^{2} - 6 r^{2} t = 6 r^{2} t \cdot (3 r t + 2 t - 1)$ $18 r^3 t^2 + 12 r^2 t^2 − 6 r^2 t=6 r^2 t* (3 r t + 2 t - 1)$

How do you factor the polynomials 18r3t2+12r2t2−6r2t18r^3t^2+12r^2t^2-6r^2t?