How do you factor y= 7x^3+28x^2 ?
1 Answer
Dec 25, 2015
Both
7x^3+28x^2 = 7x^2(x+4)
Explanation:
7x^3 = 7x^2*x
28x^2 = 7x^2*4
So:
7x^3+28x^2 = (7x^2*x)+(7x^2*4) = 7x^2*(x+4)
Both
7x^3+28x^2 = 7x^2(x+4)
7x^3 = 7x^2*x
28x^2 = 7x^2*4
So:
7x^3+28x^2 = (7x^2*x)+(7x^2*4) = 7x^2*(x+4)