How do you factor y= x^3-2x^2+x-2y=x32x2+x2 ?

1 Answer
Mar 8, 2016

For polynomials like this one, you must find a number to factor out by grouping

Explanation:

The GCF (greatest common factor) of the first two is x^2x2. The GCF of the last two is 1. So, we get:

y = x^2(x - 2) + 1(x - 2)y=x2(x2)+1(x2)

You can make the two x- 2 into one.

y = (x^2 + 1)(x - 2)y=(x2+1)(x2)

If you distribute you'll get the same thing as at the beginning. Beware: this method only works if the two expressions are the same (x - 2 in your problem)

Example: 2x + 4x^2 - 3x + 6x^22x+4x23x+6x2

2x(1 + 2x) - 3x(1 - 2x)2x(1+2x)3x(12x)

As you can see, we can't go further because we have 1 + 2x1+2x and 1 - 2x12x.

Practice exercises:

  1. Factor the following polynomials, if possible:

a ) 3x^3 + 9x^2 - 2x^2 - 6x3x3+9x22x26x

b) x^8 - x^3 + x^7 - x^2x8x3+x7x2

c). 2xy + 8x^2y^3 - 4xy^5 - 16x^2y^152xy+8x2y34xy516x2y15

Good luck, and hello from Esquimalt!