How do you factor $y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3 + 6x^2 - 4x - 24$ ?

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How do you factor $y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3 + 6x^2 - 4x - 24$ ?

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Answer 1 · 2015-12-16T06:27:16

$y = (x + 6) (x - 2) (x + 2)$ $y=(x+6)(x-2)(x+2)$

Explanation:

$y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3+6x^2-4x-24$ => factor by grouping:
$y = x^{2} (x + 6) - 4 (x + 6)$ $y=x^2(x+6)-4(x+6)$
$y = (x + 6) (x^{2} - 4)$ $y=(x +6)(x^2-4)$ => use difference of squares:
$y = (x + 6) (x - 2) (x + 2)$ $y=(x+6)(x-2)(x+2)$

Answer 2 · 2015-12-16T06:29:33

$y = (x + 2) (x - 2) (x + 6)$ $y=(x+2)(x-2)(x+6)$

Explanation:

$y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3+6x^2-4x-24$

$y = x^{2} (x + 6) - 4 (x + 6)$ $y=x^2(x+6)-4(x+6)$

$y = (x^{2} - 4) (x + 6)$ $y=(x^2-4)(x+6)$

$y = (x + 2) (x - 2) (x + 6)$ $y=(x+2)(x-2)(x+6)$

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How do you factor $y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3 + 6x^2 - 4x - 24$ ?

2 Answers

Explanation:

Explanation:

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How do you factor y=x3+6x2−4x−24y=x^3 + 6x^2 - 4x - 24 ?

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How do you factor $y = x^{3} + 6 x^{2} - 4 x - 24$ $y=x^3 + 6x^2 - 4x - 24$ ?