How do you factor y=x^3 + 8x^2 + 19x + 12y=x3+8x2+19x+12 ?

1 Answer
Gerardina C.
Jun 15, 2016

(x+1)(x+4)(x-3)(x+1)(x+4)(x−3)

Explanation:

First, use all integer negative numbers that divide the known term 12 and substitute them in x
Prove x=-1
y=(-1)^3+8*(-1)^2+19*(-1)+12=0 y=(−1)3+8⋅(−1)2+19⋅(−1)+12=0
then use Ruffini method to have:

(x^2+7x+12)(x+1)(x2+7x+12)(x+1)

x=(-7+-sqrt(49-48))/2x=−7±√49−482
x=(-7+-1)/2x=−7±12
x=-4 and x=3x=−4andx=3

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