How do you factor $y= (x-5)(x+6)^2 - (x-5)^2 (x+6)$ ?

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Answer 1 · 2018-07-04T01:18:20

$y=(x-5)(x+6)(11)$

When factorising, you want to take out anything that you can find in both parts of the equation ie in $(x-5)(x+6)^2$ and $(x-5)^2(x+6)$

Hopefully, you will notice that there is one $x-5$ and one $x+6$ in both parts

Therefore, you can "take" them out
$y=(x-5)(x+6)(x+6-(x-5))$
$y=(x-5)(x+6)(x+6-x+5)$
$y=(x-5)(x+6)(11)$

How do you factor y= (x-5)(x+6)^2 - (x-5)^2 (x+6) y= (x-5)(x+6)^2 - (x-5)^2 (x+6) ?