How do you find 4 consecutive odd integers with a sum of 18?

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Answer 1 · 2016-12-15T15:25:03

Because $x$ $x$ is not an integer there is no solution to this problem involving consecutive odd integers.

4 consecutive odd integers would be every other integer (3, 5, 7, etc.).

There for let's call the first integer $x$ $x$ .

Then the other three integers would be: $x + 2$ $x + 2$ , $x + 4$ $x + 4$ and $x + 6$ $x + 6$

Adding these four integers together gives:

$x + x + 2 + x + 4 + x + 6 = 18$ $x + x + 2 + x + 4 + x + 6 = 18$

Combining like terms and then solving gives:

$4 x + 12 = 18$ $4x + 12 = 18$

$4 x + 12 - 12 = 18 - 12$ $4x + 12 - 12 = 18 - 12$

$4 x = 6$ $4x = 6$

$\frac{4 x}{4} = \frac{6}{4}$ $(4x)/4 = 6/4$

$x = \frac{3}{2}$ $x = 3/2$

Because $x$ $x$ is not an integer there is no solution to this problem involving consecutive odd integers.