How do you find $a_{43}$ $a_43$ given 5, 9, 13, 17,...?

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How do you find $a_{43}$ $a_43$ given 5, 9, 13, 17,...?

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Answer 1 · 2016-12-13T22:05:34

See explanation.

Explanation:

From the given terms you see that the first term of the sequence is $a_{1} = 5$ $a_1=5$ and the common difference is $d = 4$ $d=4$ , so to calculate the fourty third term you can use the formula:

$a_{n} = a_{1} + (n - 1) \times d$ $a_n=a_1+(n-1)xxd$

If we substitute the given data we get:

$a_{43} = 5 + (43 - 1) \times 4 = 5 + 42 \times 4 = 5 + 168 = 173$ $a_43=5+(43-1)xx4=5+42xx4=5+168=173$ .

Answer: The 43rd term is $a_{43} = 173$ $a_43=173$

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How do you find $a_{43}$ $a_43$ given 5, 9, 13, 17,...?

1 Answer

Explanation:

$a_{n} = a_{1} + (n - 1) \times d$ $a_n=a_1+(n-1)xxd$

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How do you find a43a_43 given 5, 9, 13, 17,...?

1 Answer

Explanation:

an=a1+(n−1)×da_n=a_1+(n-1)xxd

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How do you find $a_{43}$ $a_43$ given 5, 9, 13, 17,...?

$a_{n} = a_{1} + (n - 1) \times d$ $a_n=a_1+(n-1)xxd$