How do you find a standard form equation for the line (1,4) (0,1)?

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Answer 1 · 2016-05-26T06:29:04

$3x-y+1=0$

The standard form of a linear equation in two variables representing a line is $ax+by+c=0$ .

Equation of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1)$

Hence, equation of line passing through $(1,4)$ and $(0,1)$ will be

$(x-1)/(0-1)=(y-4)/(1-4)$

or $(x-1)/-1=(y-4)/-3$

or $-3*(x-1)=-1*(y-4)$

or $-3x+3=-y+4$

or $0=3x-y+4-3$

or $3x-y+1=0$