How do you find $abs(1 + 3i)$ ?

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Answer 1 · 2016-04-14T23:12:38

$|1+3i| = sqrt(10)$

We define the modulus of a complex number $a+bi, a,b in RR$ , denoted $|a+bi|$ , as

$|a+bi| = sqrt(a^2+b^2)$

In this case, we have

$|1+3i| = sqrt(1^2+3^2) = sqrt(10)$

How do you find abs(1 + 3i)abs(1 + 3i)?