How do you find $abs( 12-5i)$ ?

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Answer 1 · 2016-03-17T10:59:06

$|12-5i|=13$

$|12-5i|$ is the modulus of complex number $12-5i$ .

Modulus of complex number $a+bi$ is given by $sqrt(a^2+b^2)$

hence $|12-5i|=sqrt(12^2+(-5)^2)=sqrt(144+25)=sqrt169=13$

How do you find abs( 12-5i)abs( 12-5i)?