How do you find $| 14 i |$ $abs( 14i )$ ?

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Answer 1 · 2016-04-04T12:23:18

$| 14 i | = 14$ $|14i| = 14$

Given a complex number $a + b i$ $a+bi$ , the modulus $| a + b i |$ $|a+bi|$ of the complex number is given by

$| a + b i | = \sqrt{a^{2} + b^{2}}$ $|a+bi| = sqrt(a^2+b^2)$

In this case, we have

$| 14 i | = | 0 + 14 i | = \sqrt{0^{2} + 14^{2}} = 14$ $|14i| = |0+14i| = sqrt(0^2+14^2) = 14$

Note that in general, for any $binRR$ , we have $|bi| = sqrt(b^2) = |b|$

Answer 2 · 2016-04-04T12:25:39

14

$|ab|=|a||b|$ .
i is unit vector in the direction of the axis of imaginaries. $|i|=1$ .

How do you find abs( 14i )|14i|abs( 14i )?