How do you find $abs( 2-2i )$ ?

Question

3173 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-06T15:32:41

The answer is $=2sqrt2$

Let $z=a +ib$ be a complex number.

Then the modulus of $z$ is

$∣z∣=∣a+ib∣=sqrt(a^2+b^2)$

so,

$∣2-2i∣=sqrt(2^2+(-2)^2)$

$=sqrt(4+4)= sqrt8=2sqrt2$

How do you find abs( 2-2i )abs( 2-2i )?