How do you find $abs(2 - 6i)$ ?

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Answer 1 · 2016-03-27T18:14:56

$|2-6i|=sqrt40$

Let $z=x+iy$ be any complex number in rectangular form.

Then its modulus is given by $|z|=sqrt(x^2+y^2)$

So in this particular case we get

$|2-6i|=sqrt(2^2+(-6)^2)=sqrt40$ .

How do you find abs(2 - 6i)abs(2 - 6i)?