How do you find abs( -2+i )? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer sente May 3, 2016 |-2+i| = sqrt(5) Explanation: Given a complex number a+bi, that number's modulus, denoted |a+bi|, is given by |a+bi| = sqrt(a^2+b^2) In this case, that gives us |-2+i| = sqrt((-2)^2+1^2) = sqrt(4+1) = sqrt(5) Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number 3+4i in the complex plane? How do I graph the complex number 2-3i in the complex plane? How do I graph the complex number -4+2i in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number 4i in the complex number plane? How do I use graphing in the complex plane to add 2+4i and 5+3i? How do I use graphing in the complex plane to subtract 3+4i from -2+2i? See all questions in Complex Number Plane Impact of this question 1321 views around the world You can reuse this answer Creative Commons License