How do you find $| 2 - i |$ $abs( 2-i )$ ?

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Answer 1 · 2016-04-08T17:25:07

$| 2 - i | = \sqrt{5}$ $|2-i|=sqrt5$

$| a + b i | = \sqrt{a^{2} + b^{2}}$ $|a+bi|=sqrt(a^2+b^2)$

Hence, $| 2 - i | = \sqrt{2^{2} + {(- 1)}^{2}} = \sqrt{4 + 1} = \sqrt{5}$ $|2-i|=sqrt(2^2+(-1)^2)=sqrt(4+1)=sqrt5$

How do you find |2−i|abs( 2-i )?