How do you find $abs( 3 - 2i)$ ?

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Answer 1 · 2016-03-24T10:40:13

$|3-2i|=3.606$

Finding $|3-2i|$ means finding the modulus of complex number $3-2i$ .

As modulus of a complex number $a+bi$ is given by $sqrt(a^2+b^2)$

$|3-2i|=sqrt(3^2+(-2)^2)=sqrt(9+4)=sqrt13=3.606$

How do you find abs( 3 - 2i)abs( 3 - 2i)?