How do you find $abs( 3-4i)$ ?

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Answer 1 · 2016-05-23T13:59:11

$|3-4i|=5$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|3-4i|$ is

$sqrt(3^2+4^2)=sqrt(9+16)=sqrt25=5$

How do you find abs( 3-4i)abs( 3-4i)?